Relation between slopes of 2 perpendicular lines in terms of a complex number ???
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Hey there !!!!!!!
Let us consider m₁ , m₂ are slopes of two lines L₁ and L₂ which are mutually perpendicular.
The product of slopes of these mutually perpendicular lines= -1
⇒⇒⇒⇒⇒ m₁m₂=-1
But we know that "i" is a complex number and its square is -1.
i²=-1
m₁m₂=-1
So, m₁m₂=i²
Hope this helped you .............
Let us consider m₁ , m₂ are slopes of two lines L₁ and L₂ which are mutually perpendicular.
The product of slopes of these mutually perpendicular lines= -1
⇒⇒⇒⇒⇒ m₁m₂=-1
But we know that "i" is a complex number and its square is -1.
i²=-1
m₁m₂=-1
So, m₁m₂=i²
Hope this helped you .............
Answered by
6
Let two lines are gven , in the slope form y = m1x + C1
y =m2x + C2
where, m1 and m2 are the slopes of given lines and C1 and C2 are y - intercepts .
we also know,
both lines will be perpendicular when ,
slope of 1st line × slope of 2nd line= -1
e.g m1 × m2 = - 1 ---------(1)
but we know,
i² = -1
use this in equation (1)
then,
m1 × m2 = (-1) = i²
hence,
m1 × m2 = i² is relation between slope of two lines in term of complex number.
y =m2x + C2
where, m1 and m2 are the slopes of given lines and C1 and C2 are y - intercepts .
we also know,
both lines will be perpendicular when ,
slope of 1st line × slope of 2nd line= -1
e.g m1 × m2 = - 1 ---------(1)
but we know,
i² = -1
use this in equation (1)
then,
m1 × m2 = (-1) = i²
hence,
m1 × m2 = i² is relation between slope of two lines in term of complex number.
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