Question

Relation between time and distance is t = ax^2 + bx where a and b are constant find retardation

Answer 1

Differenceat it and we gate ans -a/ax+b

Answer 2

Answer:

Answer:

if , t = ax^2+bx

then, differentiate both side with respect to time (t)

dt/dt = 2ax.dx/dt + b.dx/dt

1 = 2axv + bv

v(2ax + b) = 1

(2ax + b) = 1/v

Again differentiate both side with respect to time (t)

2a.dx/dt = -v^(-2)*dv/dt

2av = v^(-2)*acceleration

acceleration = -2av³

Hence,

retardation= 2av³ (ANS)

Explanation: