Question

Relation between Y, n and 6 is:
(A) Y=2n(1+0)
(B)
Y = n(+0)
(C)
Y-1(1+20
(D) 2Y = n(1+0)​

Answer 1

Answer:

We know that,

Y=3K(1−2σ)

or, σ=

2

1

(1−

2K

Y

) ----------(i)

Also, Y=2η(1+σ)

or, σ=

2η

Y

−1 ----------(ii)

Now, From (i) and (ii),

2

1

(1−

3K

Y

)=

2η

Y

−1

or, 1−

3K

Y

=

η

Y

−2

or,

Y

3

=

η

1

+

3K

1

Explanation:

this answer is of the question