Question

relation between zeros coefficients of quadratic polynomials


${3y }^ {2} + 5y - 2$
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Answer 1

3y² + 5y -2

3y²+6y-y -2

3y(y+2) -|(y+2)

(3y-|) (y+2)

y = |/3 ; y2= -2

now ,,, y + y2 = -b/a

|/3 -2 = -5/3 =-b/a ....(I)

y×y2 = c/a

|/3×-2 = -2/3 = c/a

hence proved.

if any doubt then ask.

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Answer 2

Hey mate here is ur solution :-

3y^2 + 5y -2

by splitting the middle term

3y^2 + 6y - y -2

3y (y+2) -1 (y+2)

(3y-1) (y +2)

now the zeros of polynomial are :-

3y-1=0

3y=1

y=1/3

and

y+2=0

y=-2

now the relation between zeros and cofficient

sum of zeros

=-cofficient of y/cofficient of y^2

=-5/3

product of zeros

constant / cofficient of y^2

2/3

hopes it's helps uh ❗ ❗

pls mark my ans as brainliest ☆