Math, asked by madhumita889, 11 months ago

relationalize the denominator of the following

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Answered by abdul9838
5

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Hola

Hey user here is Ans

Question

Rationalise the denominator

Answer

Step by Step explaination

 \huge \: Hola  \\  \\ </p><p></p><p></p><p>Hey \:  user  \: here \:  is \:  Ans \\  \\ </p><p></p><p></p><p> \huge \: Question </p><p></p><p> \\  \\ </p><p>Rationalise  \: the  \: denominator \\  \\ </p><p></p><p></p><p></p><p> \huge \bf \:  Answer \\  \\ </p><p></p><p></p><p> \\  \\ Step  \: by \:  Step \:  explaination \\  \\ </p><p></p><p></p><p> \bf \frac{ \sqrt{6} }{ \sqrt{2} +  \sqrt{3}  }  \\  \\  \bf \:  \frac{ \sqrt{6} ( \sqrt{2} -  \sqrt{3})  }{( \sqrt{2} +  \sqrt{3})( \sqrt{2}  -   \sqrt{3})  }  \\  \\  \bf \:  \frac{ \sqrt{6}( \sqrt{2} -  \sqrt{3}  ) }{( \sqrt{2} )^{2} - ( { \sqrt{3}) }^{2}  }  \\  \\  \bf \:  \frac{ \sqrt{6}( \sqrt{2} -  \sqrt{3}  ) }{2 - 3}  \\  \\  \bf \:   \frac{ \sqrt{12}  -  \sqrt{18} }{ - 1}  \\  \\  \frac{ \sqrt{4 \times 3} -   \sqrt{9 \times 2} }{ - 1}  \\  \\  -  \frac{2 \sqrt{3}  - 3 \sqrt{2} }{1}  \:  \: ans


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