Question

relationship between electric field and electrostatic potential​

Answer 1

The relationship between potential and field (E) is a differential: electric field is the gradient of potential (V) in the x direction. This can be represented as: Ex=−dVdx E x = − dV dx . Thus, as the test charge is moved in the x direction, the rate of the its change in potential is the value of the electric field.

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Answer 2

ELECTRIC FIELD IS GIVEN BY THE FORMULA

KQ/r^2=E

while ELECTROSTATIC POTENTIAL IS GIVEN BY

KQ/r=V

[k=9*10^-9 N^2M^2C^-2]

(r= the distance )

so the relationship is

E=V/r