Question

Relationship between Lambda and kinetic energy ?
please give me step by step explanation !​

Answer 1

Answer:

We will use the equation to find de-Broglie wavelength to find the kinetic energy of the electron with wavelength 1nm. De-Broglie wavelength of a particle is inversely proportional to the momentum of that particular body. We should know that kinetic energy and momentum of a particle is related as K. E=P22m.

The kinetic energy of the electrons accelerated through a potential difference (voltage) V was E = ½mv2 = p2/(2m) = eV and the de Broglie formula then yields λ = h/(2meV)1/2, where e and m are the charge and the mass of the electron respectively.

I think it help u

Answer 2

Answer:

We will use the equation to find de-Broglie wavelength to find the kinetic energy of the electron with wavelength 1nm. De-Broglie wavelength of a particle is inversely proportional to the momentum of that particular body. We should know that kinetic energy and momentum of a particle is related as K. E=P22m.