Question

Relationship between path difference and intensity

Answer 1

Answer:

Explanation:

A general representation of Young's double slit experiment looks like,

Now coming to formula, the relation between average intensity of light fringes observed on the screen (I) and path difference between the two waves (sinθd) emerging from both the slits is,

I=Imaxcos2πdsinθλ

where Imax= maximum intensity on the screen (i.e. intensity of the central fringe)

θ can be calculated as represented in the image.

For small values of θ, sinθ ~ yL. So the above equation can be written as,

I=Imaxcos2(πdλ⋅yL)

That's all there is regarding to relation between path difference and intensity of light in Young's double slit experiment.

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Answer 2

Answer:

In the Young's double - slit experiment, the intensity of light at a point on the screen where the path difference is λ is K,(λ being the wave length of light used). The intensity at a point where the path difference is λ/4, will be. A .