Question

❤❤relationship between phase difference and path difference❤❤❤❤❤​

Answer 1

Answer:

Let us consider 2 travelling waves having equation as follows :

$\large{ \red{1) \: y = a \sin( \omega t - kx) }}$

$\large{ \red{2) \: y = a \sin( \omega t - kx + \phi) }}$

Now , phase in wave mechanics represent the status or position of a wave ( attributed to medium particle vibration ) with respect to a specified time interval.

So in-between the above given waves , the Phase Difference is as follows :

$\blue{phase \: diff. = (\omega t - kx + \phi) - ( \omega t - kx)}$

$\blue{ \Delta phase= \phi}$

Now coming to path Difference :

Due to present of phase Difference in between waves , the position of different wave with respect to similar time intervals are different.

The positional Difference is actually called Path Difference.

Mathematically , path Difference is given as follows :

$\boxed{ \sf{ \green{ \bold{\Delta \phi = \dfrac{2\pi}{ \lambda} \times (path \: diff.)}}}}$

Answer 2

Answer:

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