relationships between momentum and kinetic energy
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Answer:
K.E=2p^2/2m
p=Sqr root of 2K.Em
Explanation:
K.E=1/2mv^2
multiply and divide by m
K.E=m^2v^2/2m
p=mv
K.E=p^2/2m
p=Sqr root of2mK.E
Answered by
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hope it helps!
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