Question

relationships between zeroes and coefficients of a polynomial x square-3 sum​

Answer 1

Answer:

Step-by-step explanation:

x²-3 = 0

x² = 3

x = ±√3

Therefore, the zeroes of the given polynomial are √3 and -√3.

Relationship between the zeroes and coefficients :-

Sum of zeroes = √3+(-√3) = √3-√3

= 0 = -x coefficient/x² coefficient

Product of zeroes = (√3)(-√3)

= -(√3)² = -3/1 = constant/x² coefficient

hope it helps

Answer 2

$\huge\fbox{\red{ᴀɴsᴡᴇʀ}}$

→ x²-3=0

→ x²=3

→ x = ± √3

→ Therefore, the zeroes of the given polynomial are √3 and -√3.

→ Relationship between the zeroes and coffieciants:-

→ Sum of zeroes = √3+(-√3) = √3+√3

→ 0= -x coefficient /x² coefficient

→ Products of zeroes =(√3)(-√3)

→ -(√3)²= -3/1 constant/x² coefficient

hope it's help you