Relative abundance of 2 isotopes of Neon Ne 20 and Ne22
are in 9:1 ratio find its average atomic mass.
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9 : 1
Let, the w% of
20
Ne=x
w% of
22
Ne=100−x
20.2=
100
x×20+(100−x)×22
2020=20x+2200−22x
2x=2200−2020=180
x=90%
∴ w% of
20
Ne=90%
w% of
22
Ne=10%
The ratio of the relative abundances of the isotopes is:
∴
20
Ne :
22
Ne
=9:1
Explanation:
I hope it this answer is correct
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