Relative density can't be 0.
but in the case of light..
m = 0
density = 0
And relative density = 0 / density of water
= 0
Explain...
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Light is an EM wave, so there is no use of calculating the relative density of light as light can pass through water or any other fluid. There are no rules of flotation of light. But, if it does then your question is wrong. Because light carries mass in a discrete amount depending upon its frequency(from where E is energy m is mass and c is speed of light.)
But, for your level you can ignore it as an exception.
prateekbana9613:
how do you get infinite=Ek?
We need infinite energy , that's why
when light is created it has no speed. Means it is at rest. when it is at rest its mass is zero and don't require energy to reach the speed. It only gains energy if it has some speed.
And it is a EM wave so we use E=hf not E=1/2m[tex]v^{2}[/tex]
Then , Ek = 1/2mv² ...... then kinetic energy will be 0 at rest...and it will never accelerates until it gets mass...
a=f/m;m=0;a=infinite
It's undefined not infinite
0/0=un;non-zero/0=infinite
and you get 0 to infinite times not 1,2,3,4.,n
If a/0 = infinite then 0×infinite must be equal to a and 0×something = 0 then a = 0
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