Question

Relative density of an oil is 0.8 is. the absolute density of an oil in CGS & SI units are

Answer 1

Answer:

Explanation:

0.8gcm^3. 800kgm^3\

Answer 2

Answer:

In the SI unit system, the oil's absolute density calculated is $800kg/m^{3}$.

In the CGS unit system, the oil's absolute density calculated is $0.8g/cm^{3}$.

Explanation:

The oil's given relative density = $0.8$

In CGS and SI unit systems, the oil's absolute density =?

As we know,

• The CGS unit is cm (C), gram (G), and second (S).
• The SI unit is the international system of units, i.e., kg, m etc.

Now,

• Relative density = $\frac{Density of oil}{Density of water}$

As we know,

• The density of water = $1000kg/m^{3}$

Therefore,

• Relative density = $\frac{Density of oil}{Density of water}$
• The oil's absolute density = oil's relative density × density of water
• Absolute density of oil = $0.8\times 1000$ = $800kg/m^{3}$

As we know, kg/m³ is the SI unit.

Therefore, in the SI unit system, the oil's absolute density calculated is $800kg/m^{3}$.

Now, in the CGS unit:

Convert kg into g and m³ into cm³.

• $1kg = 1000g$
• $1m^{3} = 10^{6}cm^{3}$

Thus,

• $1kg/m^{3} = \frac{1000}{10^{6} } g/cm^{3}$
• $800kg/m^{3}$ = $800\times \frac{1000}{10^{6} } g/cm^{3}$ = $0.8g/cm^{3}$.

Therefore, in the CGS unit system, the oil's absolute density calculated is $0.8g/cm^{3}$.