Question

Relative density of iron is 7.8. what will be the density of iron in S.I unit

Answer 1

Relative density of iron is 7.8

Density of iron = Relative density of iron × density of water

Density of water = 1000 kg/m³

Density of iron = 7.8 × 1000 = 7800 kg/m³

Answer 2

Given:

Relative density of Iron= 7.8

To find:

The density of Iron in the S.I. unit

Solution:

We can find the solution in a few simple steps-

We know that the relative density is obtained by dividing the density of the object by the density of water.

So, to calculate the destiny of Iron we will multiply its relative density with the density of water.

The density of water is taken as 1000kg per cubic meter.

Relative density of Iron= Density of Iron/ Density of water

7.8= Density of Iron/ 1000

7.8×1000= Density of Iron

Density of Iron=

$7800kg \: per \: {m}^{3}$

Therefore, the density of Iron is 7800kg/ cubic meter.