Question

Relative density of silver is 10.5 find density of silver

Answer 1

$relative \: density \: = \frac{density \: ofsubstance}{density \: of \: water}$

$density \: of \: water \: = \: 1 \: gm \: {cm}^{ - 3}$

Therefore,

$densiy \: of \: silver \: = \: 10.5 \: gm \: {cm}^{ - 3}$

Answer 2

Answer: 10,468.5  $kg/m^{3}$

Explanation:

• Relative density of a substance is defined as the ratio of density of substance to the density of water.
• Let the density of silver be x $kg/m^{3}$.
• We know that density of water is 997  $kg/m^{3}$.
• Relative density is given as 10.5.
• Relative density= $\frac{density\ of\ silver}{density\ of\ water}$

     ⇒ 10.5=$\frac{x}{997}$

     ⇒ x = 997 × 10.5

     ∴ x = 10468.5  $kg/m^{3}$.

• Hence, the required density of silver is 10,468.5  $kg/m^{3}$.

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