Question

Relative density of silver is
10.8. The density of water is 103 kg m-'.
What is the density of silver in SI unit?​

Answer 1

Relative density=Density of substance/density of water

10.8=x/103

10.8×103=x

1,112.4=x

Answer 2

Density of silver is 10800 $\mathbf{ \frac{kg}{m^{3}}}$

Step-by-step explanation:

• Given data

       $\mathbf{\textrm{Density of water(\rho _{w})}=1000 \ \frac{kg}{m^{3}}}$$\mathbf{\textrm{Density of water(\rho _{w})}=1000 \ \frac{kg}{m^{3}}}$$\mathbf{\textrm{Density of water(\rho _{w})}=1000 \ \frac{kg}{m^{3}}}$$\mathbf{\textrm{Density of water}(\rho _{w})=1000 \ \frac{kg}{m^{3}}}$

        Relative density of silver = 10.8

        $\mathbf{\textrm{Density of silver }(\rho _{Ag})=Unknown}$

• We know that relative density is ratio of density of any object to density of water.

        $\mathbf{Realtive\ density= \frac{Density\ of\ any\ object }{Density\ of\ water}}$

• On putting respective value in above equation, we get

        $\mathbf{10.8= \frac{Density\ of\ Silver }{1000}}$

• On solving, we get

        $\mathbf{\textrm{Density of silver }(\rho _{Ag})=10.8\times 1000}$

        $\mathbf{\textrm{Density of silver }(\rho _{Ag})=10.8\times 1000=10800 \ \frac{kg}{m^{3}}}$