Relative rate of SN1 and SN2 which I to propyl Bromide
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Explanation:
ANSWER
The Reactivity order for S
N
2
is
1
o
>2
o
>>3
o
Therefore, Carbocation formed in CH
3
CH
2
Br will be of Highest relative rate, and also it is less crowded.
Therefore, Answer is CH
3
CH
2
Br
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