Relative refractive index of two media is 0.80, In one of them, light has wavelength 6000 A' and travel
at 2.4 x 10 m/s. This light is refracted into the second medium. Its frequency in the second medium is
a) 4 x 10!4 Hz
b) 6 x 10W H2
c) 2 x 10 Hz d) 3,2 x 10' Hz[ a
The speed of light in glass of refractive Inde
Answers
Answer:
Answer
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The frequency in the second medium is (a) 4 x 10^14 Hz.
Given: The relative refractive index of two media is 0.80, In one of them, light has a wavelength of 6000 A' and travels at 2.4 x 10 m/s.
To Find: The frequency in the second medium.
Solution:
- We know that the refractive index depends upon the speed of the particle in the particular media. The Refractive index is inversely proportional to the speed of the particle.
- We also know that the frequency is an inherent property of the source and remains constant throughout. So, the change in the refractive index does not affect the frequency.
- The relation between frequency and wavelength can be represented by the formula,
f = c / λ ...(1)
Where f = frequency, c = velocity of light, λ = wavelength of light.
Coming to the numerical, it is given that,
The relative refractive index = 0.80
The wavelength of light = 6000 Å
The speed of light in first medium = 2.4 x 10^8 m/s
Now, as we know that the frequency does not change with a change in refractive index, so we can find the frequency in the second medium by putting the respective values in (1),
f = c / λ
⇒ f = ( 2.4 x 10^8 ) / ( 6000 x 10^-10 ) Hz
⇒ f = 4 x 10^14 Hz
Hence, the frequency in the second medium is (a) 4 x 10^14 Hz.
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