Question

rema
quot
rem
divi
(C) 5
(d) None of the
Olo. A number X is successively divided by
11, and 3 leaving remainder 6, 2 and
1, respectively. X when
divided
successively by 3, 4 and 11 leaves
remainder
[CMAT 2015)
(a) 6, 0,0 (b) 0, 1, 2
(c) 0, 0,6 (d) 1, 2, 6
on when divided by a divisor
and
div
W1
res
(a)​

Answer 1

Answer:

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Step-by-step explanation:

According to Euclid's Division Lemma,If a and b are two positive integers such that

"a" is divided by "b" then there exists two uniques integers "m" and "n" such that

a=bm+n,0≤n<b

It is given that when a natural number x is divided by 5,the remainder is 2.

So for an integer m, we have

x=5m+2

Also when a natural number y is divided by 5, the remainder is 4

So for an integer n, we have

y=5n+4

⇒x+y=5m+2+5n+4=5(m+n)+6=5(m+n+1)+1

This shows that when x+y is divided by 5, we get 1 as a remainder.

Thus, by given condition

z=1

So, the value  of 32z−5 is given by

32z−5=32(1)−5=32−5=−1