Question

remainder 1.
9. Find the greatest 4-digit number which when divided by 36, 30, 24 and 15

leaves a remainder 13 in each case.
non hut creater than 999, which is exactly divis
10
ind.1​

Answer 1

Answer:

Let the greatest 4-digit number be “N”.

So, N is divisible by 7, 10, 15, 21 and 28.

=>N=K×LCM(7,10,15,21,28)

Note: K is any natural number such that K* LCM gives us a 4-digit number.

=>N=K×420

=>N = 420K

Now the greatest 4-digit number is 9999.

R[9999420]=339

=>(9999−339)=9660 is divisible by 420

=>9660=420×23

=>K=23