Question

remainder
(2x square+3x+1) by (x+1)​

Answer 1

$\large\sf\underline{Given:}$

• $\sf\frac{2x^{2}+3x+1}{x+1}$

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$\large\sf\underline{To\:find:}$

• Remainder = ??

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$\large\sf\underline{Solution:}$

$\sf\frac{2x^{2}+3x+1}{x+1}$

• Solving by middle term breaking of $\sf\:2x^{2}+3x+1$

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$\sf\implies\:\frac{2x^{2}+(2+1)x+1}{x+1}$

$\sf\implies\:\frac{2x^{2}+2x+1x+1}{x+1}$

$\sf\implies\:\frac{2x^{2}+2x+x+1}{x+1}$

$\sf\implies\:\frac{2x(x+1)+1(x+1)}{x+1}$

$\sf\implies\:\frac{(2x+1)(x+1)}{x+1}$

$\sf\implies\:\frac{(2x+1)\cancel{(x+1)}}{\cancel{x+1}}$

$\large{\mathfrak\purple{\implies\:2x+1}}$

‎So remainder is found to be $\large{\mathfrak{\implies\:2x+1}}$

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‎!! Hope it helps !!