Question

remainder and factor theorm​

Answer 1

$\huge{\bold{\red{\star{\pink{Heya!}}}}}$

$2x + 1 = 0$

$x = \frac{ - 1}{2}$

Putting the value of x in p(x)

$= 4 \times { \frac{ - 1}{2} }^{3} - 2 \times { \frac{ - 1}{2} }^{2} + k \times \frac{ - 1}{2} + 5 = - 10$

$= 4 \times \frac{ - 1}{8} - 2 \times \frac{ 1}{4} - \frac{k}{2} + 5 = - 10$

$= \frac{ - 1}{2} - \frac{1}{2} - \frac{k}{2} + 5 = - 10$

$\frac{ - 1 - 1 - k + 10}{2} = 10$

$8 - k = - 20$

$k = 28$

Answer 2

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