Question

Remainder of x²+ax²+6x+a is divided by (x+a)

Answer 1

x+a=0

x=-a

putting in the equation

(-a)²+a(-a)²+6(-a)+a

=a²+a³-6a+a

=a³+a²-5a

=a(a²+a-5)

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Answer 2

Hi friend

Hi friendYour answer

Hi friendYour answerLet f(x) = x³ - ax² + 6x - a

Hi friendYour answerLet f(x) = x³ - ax² + 6x - aSo,

Hi friendYour answerLet f(x) = x³ - ax² + 6x - aSo,When,

Hi friendYour answerLet f(x) = x³ - ax² + 6x - aSo,When,f(a) = x³ - ax² + 6x - a

Hi friendYour answerLet f(x) = x³ - ax² + 6x - aSo,When,f(a) = x³ - ax² + 6x - a=> (a)³ - a×(a)² + 6×a - a

Hi friendYour answerLet f(x) = x³ - ax² + 6x - aSo,When,f(a) = x³ - ax² + 6x - a=> (a)³ - a×(a)² + 6×a - a=> a³ - a³ + 6a - a

Hi friendYour answerLet f(x) = x³ - ax² + 6x - aSo,When,f(a) = x³ - ax² + 6x - a=> (a)³ - a×(a)² + 6×a - a=> a³ - a³ + 6a - a=> 5a

Hi friendYour answerLet f(x) = x³ - ax² + 6x - aSo,When,f(a) = x³ - ax² + 6x - a=> (a)³ - a×(a)² + 6×a - a=> a³ - a³ + 6a - a=> 5aTherefore,

Hi friendYour answerLet f(x) = x³ - ax² + 6x - aSo,When,f(a) = x³ - ax² + 6x - a=> (a)³ - a×(a)² + 6×a - a=> a³ - a³ + 6a - a=> 5aTherefore,Remainder = 5a

Hi friendYour answerLet f(x) = x³ - ax² + 6x - aSo,When,f(a) = x³ - ax² + 6x - a=> (a)³ - a×(a)² + 6×a - a=> a³ - a³ + 6a - a=> 5aTherefore,Remainder = 5aHOPE IT HELPS

Hi friendYour answerLet f(x) = x³ - ax² + 6x - aSo,When,f(a) = x³ - ax² + 6x - a=> (a)³ - a×(a)² + 6×a - a=> a³ - a³ + 6a - a=> 5aTherefore,Remainder = 5aHOPE IT HELPS#ARCHITECTSETHROLLINS

Hi friendYour answerLet f(x) = x³ - ax² + 6x - aSo,When,f(a) = x³ - ax² + 6x - a=> (a)³ - a×(a)² + 6×a - a=> a³ - a³ + 6a - a=> 5aTherefore,Remainder = 5aHOPE IT HELPS#ARCHITECTSETHROLLINS✯ BRAINLY STAR ✯