Question

remainder of x3-ax2+6x-a if divided by x-a

Answer 1

Answer:

Here, p(x)=x 3+ax 2+6x−a, and the zero of x−a is a

So, p(a)=a 3+a×a 2+6×a−a =2a 3+5a

So, by the Remainder Theorem, 2a 3+5a is the remainder when x 3+ax 2+6x−a is divided by x−a.