Question

Remainder when 2(8!)-21(6!) divides 14(7!)+14(13!)

Answer 1

Answer:

Remainder =0

Step-by-step explanation:

We are given that 2(8!)-21(6!) divides  14(7!)+14(13!)

We have to find the remainder

Remainder is defined as the number remaining when dividened divided by divisor.

2(8!)-21(6!)=$2\times 8\times 7!-3\times 7\times 6!$

2(8!)-21(6!)=$2\cdot 7!-3\cdot7!$

2(8!)-21(6!)=7!(2-3)=-7!

14(7!)+14(13!)=14(7!+13!)

$\frac{14(7!)+14(13!)}{2(8!)-21(6!)}=\frac{14(7!)+13!)}{-7!}$

$\frac{14(7!)+14(13!)}{-7!}$=$\frac{-14(7!)}{7!}-\frac{14(13!)}{7!}$

=0-0=0

Hence, when 2(8!)-21(6!) divides 14(7!)+14(13!) then we get remainder zero.