Math, asked by shivamarora5433, 1 year ago

Remainder when a number 2851*(2862)(2862)*(2873)(2873)(2873) is divided by 23 is?

Answers

Answered by knjroopa
5

Answer:

18

Step-by-step explanation:

Given  

Remainder when a number 2851*(2862)(2862)*(2873)(2873)(2873) is divided by 23 is

So we need to divide the numbers. First we can write this as

2851 x (2862)^2 x (2873)^2 / 23

So remainder upon dividing by 23 will be 22 x 10 x 10 x 21 x 21 x 21

By dividing these numbers by 23 we get 22 x 8 x 441 x 21 (100 / 23 = 8(remainder)

22 x 21 x 8 x 4 / 23

462 x 32 / 23

462/23 = 2 (remainder)

32 / 23 = 9(remainder)

So 9 x 2 = 18

Now the remainder is 18

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