Remainder when a number 2851*(2862)(2862)*(2873)(2873)(2873) is divided by 23 is?
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5
Answer:
18
Step-by-step explanation:
Given
Remainder when a number 2851*(2862)(2862)*(2873)(2873)(2873) is divided by 23 is
So we need to divide the numbers. First we can write this as
2851 x (2862)^2 x (2873)^2 / 23
So remainder upon dividing by 23 will be 22 x 10 x 10 x 21 x 21 x 21
By dividing these numbers by 23 we get 22 x 8 x 441 x 21 (100 / 23 = 8(remainder)
22 x 21 x 8 x 4 / 23
462 x 32 / 23
462/23 = 2 (remainder)
32 / 23 = 9(remainder)
So 9 x 2 = 18
Now the remainder is 18
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