Question

remainder. x3 – 6x2 + 11x – 6 ÷(x-3)
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Answer 1

Given f(x)=x

3

−6x

2

+11x−6

Divisor is (x+2)

⇒a=−2

Therefore, according to remainder theorem

R=f(a)

=f(−2)

=(−2)

3

−6(−2)

2

+11(−2)−6

=−60

Answer 2

Given f(x)=x³ −6x² +11x−6

Divisor is (x+2)

⇒a=−2

Therefore,

according to remainder theorem

R=f(a)

=f(−2)

=(−2)³ −6(−2)² +11(−2)−6

=−60

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