Math, asked by vmanjot0, 1 month ago

remash invested rs 4287500 for future of his two daughters aged 10 and 15 such that they may get equal amounta when each of them reach the eged the age of 20 years the original amount of rs 4287500 has been insttuTed to be invest 10% p.a simple interest find the amount. invested. by remash for her elders. daughter​

Answers

Answered by RvChaudharY50
0

Solution :-

Let us assume that, ramesh invested Rs.x for her elder daughter .

so, for elder daughter :-

→ Principal = P = Rs.x

→ Time = T= 20 - 15 = 5 years

→ Rate = 10% per annum .

then,

→ Amount recieved = P + SI = P + (P * R * T)/100 = x + {(x * 5 * 10)/100} = x + (x/2) = Rs.(3x/2)

and, for younger daughter :-

→ Principal = P = Rs.(4287500 - x)

→ Time = T= 20 - 10 = 10 years

→ Rate = 10% per annum .

then,

→ Amount recieved = P + SI = P + (P * R * T)/100 = (4287500 - x) + {(4287500 - x) * 10 * 10)/100} = (4287500 - x) + (4287500 - x) = Rs. 2(4287500 - x)

since both daughters gets same amount .

A/q,

→ 3x /2 = 2(4287500 - x)

→ 3x = 4 * 4287500 - 4x

→ 7x = 4 * 4287500

→ x = Rs.2450000 (Ans.)

Hence, the amount invested by ramesh for her elder daughter is Rs.2450000 .

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