Reminder in (x^49+49)/(x+1)
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5
So.. Let f(x) = x^49 +49
If we divide it by (x+1)..then the remainder is.. (By remainder theorem)=f(-1)=(1)^49 +49=-1+49=48
If we divide it by (x+1)..then the remainder is.. (By remainder theorem)=f(-1)=(1)^49 +49=-1+49=48
Answered by
1
here is your solution
49(x+x+1)
49(2x+1)
49(x+x+1)
49(2x+1)
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