Math, asked by farisaladasi2006, 5 months ago

Remove brackets and simplify: x(3x + 2)(x - 1) + 5x^2. what is the coefficient of
x^2?​

Answers

Answered by Anonymous
4

Answer:

4

Step-by-step explanation:

x ( 3x + 2 ) ( x - 1 ) + 5x^2

= [ x ( 3x ) + x ( 2 ) ] ( x - 1 ) + 5x^2

= ( 3x^2 +2x ) ( x - 1 ) + 5x^2

= x ( 3x^2 ) + x ( 2x ) - 1 ( 3x^2 ) - 1 ( 2x ) + 5x^2

= 3x^3 + 2x^2 - 3x^2 - 2x + 5x^2

= 3x^3 + 2x^2 + 5x^2 - 3x^2 - 2x

= 3x^3 + 4x^2 - 2x

Therefore, the coefficient of  x^2 is 4.

Answered by dhairyaj017
1

Step-by-step explanation:

( 3x² + 2x ) ( x - 1 ) + 5x²

3x³ - 3 + 2x² - 2 + 5x²

3x³ -5 + 7x²

as 7x² is the term in which x² comes ... therefore 7 is the coefficient of x²

EXPLANATION :

first we have to multiply the values according to bodmas and then we have to simplify the answer and you will get the coefficient of x²

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