Question

Remove finish direction at a speed of 6 metre per second and 30 degree east of north at the speed of 6 metre per second the magnitude of the relative velocity

Answer 1

magnitude of their relative velocity is 6m/s

Ram moves in east direction at a speed of 6 m/s and shyam moves 30° east of north at a sleed of 6m/s. The magnitude of their relative velocity is....

velocity of Ram, $v_R$ = 6 i

velocity of Shyam , $v_S$ = 6(sin30° i + cos30° j)

= 6(1/2 i + √3/2 j)

= 3i + 3√3 j

now relative velocity of Ram with respect to Shyam , $v_{RS}$ = 6i - (3i + 3√3j)

=3i - 3√3 j

magnitude of relative velocity, |v_(RS)| = {3² + (-3√3)²}

= √(9 + 27)

= 6 m/s

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Answer 2

$\huge\bold\purple{Answer:-}$

Velocity of Ram = 6i

Velocity of Shyam = 6Sin30i + 6Cos30j

Relative velocity = 6i - 6Sin30i - 6Cos30j

= 6i - 3i - 3√3j

= 3i - 3√3j

Magnitude of relative velocity = sqrt(3^2 + (3√3)^2)

= 6 m/s