Math, asked by Shadow8793, 4 months ago

Removing all the spades from the deck of cards.what is the probability that she takes ouT a jack card other than the heat jack?

Answers

Answered by ummayleenah2012
0

Answer:

ANSWER

Total no. of cards in a pack =52

After removing red-colored - jack, queen, king, and aces,

No. of cards =52−8=44 and

No. of red cards =26−8=18.

Solution(i):

No. of black queens =2

Therefore,

2

C

1

( Selecting 1 out of 2 items) times out of

44

C

1

( Selecting 1 out of 44 items) a black queen is picked.

Let E be the event of getting a black queen from pack

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

44

C

1

2

C

1

=

44

2

=

22

1

Solution(ii):

No. of red cards =18

Therefore,

18

C

1

( Selecting 1 out of 18 items) times out of

44

C

1

( Selecting 1 out of 44 items) a red card is picked.

Let E be the event of getting a red card from the pack

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

44

C

1

18

C

1

=

44

18

=

22

9

Solution(iii):

No. of black jack cards =2

Therefore,

2

C

1

( Selecting 1 out of 2 items) times out of

44

C

1

( Selecting 1 out of 44 items) a black jack card is picked.

Let E be the event of getting a black jack card from the pack

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

44

C

1

2

C

1

=

44

2

=

22

1

Solution(iv):

No. of picture cards =12−6=6 ..... (As red cards are removed and there are 6 red picture cards )

Therefore,

6

C

1

( Selecting 1 out of 6 items) times out of

44

C

1

( Selecting 1 out of 44 items) a picture card is picked.

Let E be the event of getting a picture card from pack

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

44

C

1

6

C

1

=

44

6

=

22

3

Step-by-step explanation:

Hope it's helpful

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