Math, asked by hezekiahwoodrup04, 2 months ago

Remy stands on a dock at the edge of a lake represented by point C. Points A and B represent two buoys anchored in the lake. Remy plans to swim from C to A, then to B, and then back to C. The shortest distance from Remy to the swim route AB¯ is 60 meters and is measured from C to D.

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Answered by Anonymous
7

In ∆ ADC

cos 43° = CD/AC

0.73 = 60/AC

AC = 60/0.73

AC = 82.19 = 82.2 meter

Also

tan 43° = AD/CD

0.93 = AD/60

AD = 60 × 0.93

AD = 55.8 metres

Simy , In ∆ BCD

cos 27° = CD/BC

0.89 = 60/BC

BC = 60/0.89

BC = 67.4 meters

Also

tan 27° = BD/CD

tan 27° = BD/60

BD = 0.51 × 60

BD = 30.6 metres

Adding all

AC + AD + BD + BC

82.2 + 55.8 + 67.4 + 30.6

236 metres

Answered by adityaaryaas
3

Answer:

236m.

please find the attached image.

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