Question

renationalish denominator of
$\frac{7 + \sqrt{3} }{ \sqrt{7} - \sqrt{2} }$
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Answer 1

Answer:

Heyya !! here is you answer :

Step-by-step explanation:

$= \frac{7+\sqrt{3}}{\sqrt{7}-\sqrt{2}}\\\\\\= \frac{7+\sqrt{3}}{\sqrt{7}-\sqrt{2}}*\frac{\sqrt{7}+\sqrt{2}}{\sqrt{7}+\sqrt{2}}\\\\\\= \frac{(7+\sqrt{3})(\sqrt{7}+\sqrt{2})}{(\sqrt{7})^2-(\sqrt{2})^2}\\\\\\=\frac{7\sqrt{7}+7\sqrt{2}+\sqrt{21}+\sqrt{6}}{7-2}\\\\\\= \frac{7\sqrt{7}+7\sqrt{2}+\sqrt{21}+\sqrt{6}}{5}$

Hope it helps you mate :)

Answer 2

See the photo attached for solution