Question

rene is 6 years older than her younger sister. After 10 years the sum of their ages will be 50 years. find their present age through linear equation.

​

Answer 1

Answer:

Rene's age=18

Her younger sister's age= 12

Step-by-step explanation:

let younger sister's age= 'x'

and Rene's age= 'y'

case1: Rene is 6 years older than her sister

therefore, x+6=y, y-x=6----(i)

case2:After 10 years sum of their ages is 50

sister's age after 10 years=x+10

Rene's age after 10 years= y+10

Therefore, x+10+y+10=50

x+y+20= 50

y+x=50-20=30----(ii)

Now given equations are:

y-x=6----(i)

y+x=30----(ii)

on adding (i) and (ii)

2y=36

y=18

x=y-6=18-6=12