Rene is 6 years older than her younger sister .After 10 years the sum of there ages will be 50 years . find their present ages
Answers
Given :
- Rene is 6 years older than her younger sister.
- After 10 years the sum of there ages will be 50 years.
To find :
- Their present ages =?
Step-by-step explanation :
The present age of Rene's younger Sister be, x.
Then, the present age of Rene's be, x + 6.
It is Given that,
After 10 years the sum of there ages will be 50 years .
So,
After 10 years Rene's age will be = x + 10
After 10 years Rene's younger sister age will be = x + 6 + 10.
According to the question,
[(x + 6) + 10] + [x + 10] = 50
[(x + 16) + (x + 10)] = 50
2x + 26 = 50
2(x + 13) = 50
x + 13 = 50/2
x + 13 = 25
x = 25 - 13
x = 12
Therefore, We got the value of, x = 12.
Hence,
The age of Rene's younger sister = x = 12 years
The age of Rene = x + 6 = 18 years
Answer:
Present ages of Rene and her sister are 18 years and 12 years respectively.
Given :
➛Rene is 6 years older than her younger sister.
➛After 10 years the sum of there ages will be 50 years.
To find :
Present ages of Rene and her sister.
Solution:
We are given,
➛Rene is 6 years older than her younger sister.
➛After 10 years the sum of there ages will be 50 years.
➞Let, The present age of Rene's younger Sister be, m.
➞Then, the present age of Rene's be, m + 6.
According to given condition,
After 10 years Rene's age will be = m + 10
After 10 years Rene's younger sister age will be = m + 6 + 10.
⇛{(m + 6) + 10} + {m + 10} = 50
⇛{(m + 16) + (m + 10)} = 50
⇛2m + 26 = 50
⇛2(m + 13) = 50
⇛m + 13 = 50/2
⇛m + 13 = 25
⇛m = 25 - 13
⇛m = 12
Hence,
The age of Rene's younger sister = m = 12 years
The age of Rene = m + 6 = 18 years