Question

rene is 6 years older than her younger sister.after 10 years the sum of their ages will be 50 years.find their ages

Answer 1

let the age of younger sister be X and rene=x+6
after10 years younger sister age=x+10and rene=x+10+6
x+10+x+16=50
2x+26=50
x=50-26/2=12
rene=18 years
younger sister=12years

Answer 2

Let the present age of Rene's younger sister be x
The present age of Rene be x + 6
After 10 years the sum of their ages = 50 years
A/q,
=> [(x + 6) + 10] + [x + 10]  = 50 
=> [(x + 16) + (x + 10)] = 50
=> 2x + 26 = 50
=> 2(x + 13) = 50
=> x + 13 = 50/2
=> x + 13 = 25
=> x = 25 - 13
=> x = 12
The age of Rene's younger sister = x = 12 years
The age of Rene = x + 6 = 18 years