Question

Rene is 6 years older than her younger sister. After 10 years, the sum of their ages will be 50 years. How do you find their present ages?

Answer 1

Answer:
18, 12
Explanation:
Let's have R be Rene's age.
R
And we have a younger sister who is 6 years younger than Rene:
R
−
6
In 10 years, the sum of their ages will be 50. So in 10 years Rene will be:
R
+
10
and her sister will be
R
−
6
+
10
and the two added together will be 50:
(
R
+
10
)
+
(
R
−
6
+
10
)
=
50
How old are they now?
(
R
+
10
)
+
(
R
−
6
+
10
)
=
50
2
R
+
14
=
50
2
R
=
36
R
=
18
and her sister is
R
−
6
=
18
−
6
=
12


( Don’t Write The Numbers In a Vertical Line)