Question

Renna pushes the elevator button, but the elevator does not move. The mass limit for the elevator is
450
450450 kilograms (
kg
kgstart text, k, g, end text), but Renna and her load of identical packages mass a total of
620
 
kg
620kg620, start text, k, g, end text. Each package has a mass of
37.4
 
kg
37.4kg37, point, 4, start text, k, g, end text.
Write an inequality to determine the number of packages,
p
pp, Renna could remove from the elevator to meet the mass requirement.

What is the minimum whole number of packages Renna needs to remove from the elevator to meet the mass requirement?

Answer 1

$\Large{\underline{\underline{\bf{Correct \: Question :}}}}$

Renna pushes the elevator button, but the elevator does not move. The mass limit for the elevator is 450 kg, but Renna and her load of identical packages mass a total of 620 kg. Each package has a mass of 37.4 kg and mass of Reena is 76 kg .Write an inequality to determine the number of packages, Renna could remove from the elevator to meet the mass requirement. What is the minimum whole number of packages Renna needs to remove from the elevator to meet the mass requirement?

$\rule{200}{2}$

$\Large{\underline{\underline{\bf{Solution :}}}}$

As, it is given that mass of Reena = 76 kg

Mass of 1 packet = 37.4 kg

Total Mass elevator can hold = 450 kg.

So, A.T.Q

If we will subtract mass of Reena from the total mass and will devide by mass of 1 packet elevator can hold we can get the Number of packets.

$\sf{→Number \: of \: packets = \frac{450 - 76}{37.4}} \\ \\ \sf{→Number \: of \: packets = \frac{\cancel{374}}{\cancel{37.4}}} \\ \\ \sf{→Number \: of \: packets = 10}$

Answer 2

≛ Question :-

(in attachment)...

≛ Given that :-

• Mass of Reena = 76 kg
• Mass of 1 packet = 37.4 kg
• Total Mass that elevator can hold = 450 kg

$\huge{\boxed{\mathfrak{\underline{\purple{Solution!}}}}}$

So, according to the condition

The number of packets...

$= \frac{450 - 76}{7.4}$

$= \frac{374}{37.4}$

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