Rent is a rectangle with its dimensions in metres. It's diagonals meet at o. If or=2x+4,ot=3x+1.find 1.x
2.RN
3.TE.
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If OR= 2x+4 AND OT= 3x+1!..
Therefore,
2(2x+4)=2(3x+1) [Since, Diagonals of a Rectangle are equal]
=》2x+4=3x+1
=》4-1=3x-2x
=》x=3.......(i)
RN=2(OR) [Since, Diagonals bisect each other in a Rect.]
=》RN=2(2x+4)
= 2[2(3)+4] [On putting the value of x]
= 2[6+4]
= 12+8
= 20
Therefore, RN=20.....(ii)
Similarly, TE=2(OT) [Since, Diagonals bisect each other in a Rect.]
=》TE=2(3x+1)
= 2[3(3)+1] [On putting the value of x]
= 2[9+1]
= 18+2
= 20
Therefore, TE=20.....(iii)
__________ALTERNATIVE METHOD_______
TE=RN=20[Since, Diagonals of a Rect. are equal]
Therefore,
2(2x+4)=2(3x+1) [Since, Diagonals of a Rectangle are equal]
=》2x+4=3x+1
=》4-1=3x-2x
=》x=3.......(i)
RN=2(OR) [Since, Diagonals bisect each other in a Rect.]
=》RN=2(2x+4)
= 2[2(3)+4] [On putting the value of x]
= 2[6+4]
= 12+8
= 20
Therefore, RN=20.....(ii)
Similarly, TE=2(OT) [Since, Diagonals bisect each other in a Rect.]
=》TE=2(3x+1)
= 2[3(3)+1] [On putting the value of x]
= 2[9+1]
= 18+2
= 20
Therefore, TE=20.....(iii)
__________ALTERNATIVE METHOD_______
TE=RN=20[Since, Diagonals of a Rect. are equal]
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