Math, asked by anjalikumari5th, 1 year ago

Renu invested an amount of rupees 13900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11 % p.a. respectively. If the total amount of simple interest earned in 2 years is rupees 3508, what was the amount invested in scheme B?
A. 6400
B. 6000
C. 4200
D. None

Answers

Answered by gaintboy70509000
0

step-by-step explanation:

Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).

Then,

(x×14×2100)+((13900−x)×11×2100)=3508

⇒ 28x - 22x = 350800 - (13900 x 22)

⇒ 6x = 45000

⇒ x = 7500.

So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.


anjalikumari5th: Can't understand!
Answered by Anonymous
3
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Renu invested an amount of rupees 13900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11 % p.a. respectively. If the total amount of simple interest earned in 2 years is rupees 3508, what was the amount invested in scheme B?
A. 6400✔✔
B. 6000
C. 4200
D. None

==================☟

Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).



 28x - 22x = 350800 - (13900 x 22)

 6x = 45000

 x = 7500.

So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.

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