Physics, asked by sufiyaperven, 5 hours ago

Renu is walking along a park with constant velocity .The length and the breadth of the park is 7m and 5m respectively . Find the displacement after 2.5 rounds​

Answers

Answered by nirman95
2

Given:

Renu is walking along a park with constant velocity .The length and the breadth of the park is 7m and 5m respectively.

To find:

Displacement after 2.5 rounds?

Calculation:

  • Let's assume that Renu started from a particular vertex of the rectangle.

  • After 2 complete rounds, Renu will reach back to her starting point.

  • In the next 1/2 or 0.5 rounds, she will reach the diametrically opposite vertex of the rectangle.

So, the displacement (being shortest length between starting and stopping point) will be the diagonal.

 \therefore \: d =  \sqrt{ {7}^{2}  +  {5}^{2} }

 \implies \: d =  \sqrt{ 49 + 25}

 \implies \: d =  \sqrt{74}

 \implies \: d =  8.6 \: m

Answered by shardakuknaa
0

Answer:

Given:

Renu is walking along a park with constant velocity .The length and the breadth of the park is 7m and 5m respectively.

To find:

Displacement after 2.5 rounds?

Calculation:

Let's assume that Renu started from a particular vertex of the rectangle.

After 2 complete rounds, Renu will reach back to her starting point.

In the next 1/2 or 0.5 rounds, she will reach the diametrically opposite vertex of the rectangle.

So, the displacement (being shortest length between starting and stopping point) will be the diagonal.

\therefore \: d = \sqrt{ {7}^{2} + {5}^{2} }∴d=

7

2

+5

2

\implies \: d = \sqrt{ 49 + 25}⟹d=

49+25

\implies \: d = \sqrt{74}⟹d=

74

\implies \: d = 8.6 \: m⟹d=8.6m

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