Question

Renu purchases two bags of fertiliser of weights 75 kg and 69 kg. Find the maximum value of weight which can measure the weight of the fertiliser exact number of times. 70 om

Answer 1

Given that:

• Renu purchases two bags of fertiliser of weights 75 kg and 69 kg.

To Find:

• The maximum value of weight which can measure the weight of the fertiliser exact number of times.

Concept:

• We have to find the HCF of weight of both of the bags then we get the maximum value of weight which can measure the weight of the fertiliser exact number of times.

Finding the maximum value of weight:

Using prime factorisation method.

• Factors of 75 = 3 × 5 × 5
• Factors of 69 = 3 × 23

HCF (75, 69) = 3

Hence,

• The maximum value of weight is 3 kg.

Answer 2

Answer:

Given :-

• Renu purchases two bags of fertiliser of weights 75 kg and 69 kg.

To Find :-

• What is the maximum value of weight which can measure the weight of the fertiliser exact number of times.

Solution :-

Given :

$\leadsto$ The weight of first fertiliser bag = 75 kg

$\leadsto$ The weight of second fertiliser bag = 69 kg

As we know that :

$\sf\boxed{\bold{\pink{HCF\: or\: Highest\: Common\: Factor\: :-}}}$

$\implies$ The HCF (Highest Common Factor) is the largest common factor that two or more number have.

Now, we have to find the maximum value of weight which can measure the weight of the fertiliser exact number of times :

For finding the maximum value of weight we have to find the H.C.F of 75 and 69 :

$\mapsto$ 75 :

$\implies \sf \sf\bold{3} \times 5 \times 5$

$\mapsto$ 69 :

$\implies \sf \sf\bold{3} \times 23$

Hence, the HCF of 75 and 69 is :

$\longrightarrow \sf\bold{\red{3}}$

$\therefore$ The maximum value of weight is 3 kg , which can measure the weight of the fertiliser exact number of times.