Question

Renu purchases two bags of fertiliser of weights 75 kg and 69 kg. Find the maximum
value of weight which can measure the weight of the fertiliser exact number of times.

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Answer 1

In order to:

Find the maximum weight, we have to find the H.C.F. of:

$\huge\boxed{\sf{75\:and\:69}}$

So:

$\implies$ Factors of 75 = 3 × 5 × 5

$\implies$ Factors of 69 = 3 × 69

$\implies$ H.C.F. of 75 and 69 = 3

Hence:

The maximum value of weight which can measure the weight of the fertilizer exact number of times is 3 kg.

Answer 2

$\huge \boxed{ \underline{ \underline{ \bf{Answer}}}}$

Given :- Renu purchases two bags of fertiliser

             Than the Weights of 2 bags  :  75 kg and 69 kg

To Find :- The maximum  value of weight.

√ For finding the maximum value we should have to find H.C.F of  75 and 69.

Now, Let us find the prime factors of 75 and 69.

⇒ 75 = 3 × 5 × 5

⇒ 69 = 3 × 23

3 is the only common prime factor. ( Common in both ).

Hence, 3 is the H.C.F of 75 and 69.

Atlast, Conclusion of the whole Answer :-

• The maximum value of weight which can measure the weight of the fertilizer exact number of times = 3kg.