Math, asked by shivamyadav789757, 4 months ago

Renu's mother is four times as old as Renu. After 5
years, her mother will be three times as old as she
will be then. What are their present ages?​

Answers

Answered by libnaprasad
9

Answer:

Renu's present age is 10 years and her mother's present age is 40 years.

Step-by-step explanation:

Let Renu's present age is x years

Then her mother's present age is 4x years

After 5 years , Renu's age will be x+5 years

After 5 years , her mother's age will be 4x+5 years.

By given condition,

4x+5=3(x+5) or 4x−3x=15−5 or x=10 ; 4x=4 ; 4×10=40.

Therefore, Renu's present age is 10 years and her mother's present age is 40 years.

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Answered by plaguedr007
2

Step-by-step explanation:

let, the present age of Ranu's mother be 'x'(years)

and, present age of Ranu be 'y'(years)

Case I- 4x+y=0--------(i)

Case II- 5(X+3y)=0

5x+15y=0--------(ii)

plotting them in graph

for equation (I)

|X| -2 | -3 |

|Y| 8 | 12 |

for equation (ii)

|X| 6 | 9 |

|Y| 2 | 3 |

now plot these points on a graph and you will get two lines which will intersect in a single point and that single point if you take the value of (X,y). the value of X will be Ranu's mother, and the y will be Ranu's age HOPE THIS WOULD HELP!!

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