Renu sold an article at a loss of 8 percent.Had she bought it at 10% less and sold for 36 rupees more,she would have gained 20%.find the cost price of the article
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Let the C.P = Rs. 100
Loss = 8%
S.P = C.P*(100-L)/100
= 100*92/100 = Rs.92
Now, if she had bought it for 10% less
C.P = 100 - 100*10/100 = Rs.90
Gain = 20%
S.P = C.P*(100+P)/100 = 90*120/100 = Rs.108
Now we can see that the difference in S.P's on assumed C.P(100 Rs.) = 108 -92 = Rs. 16
Actual S.P difference has to be Rs.36
16(difference)==== 100(C.P)
36(difference)==== X (C.P)
X = 36*100/16 = Rs. 225
Hence C.P of article = rs.225
Hope this helps
Loss = 8%
S.P = C.P*(100-L)/100
= 100*92/100 = Rs.92
Now, if she had bought it for 10% less
C.P = 100 - 100*10/100 = Rs.90
Gain = 20%
S.P = C.P*(100+P)/100 = 90*120/100 = Rs.108
Now we can see that the difference in S.P's on assumed C.P(100 Rs.) = 108 -92 = Rs. 16
Actual S.P difference has to be Rs.36
16(difference)==== 100(C.P)
36(difference)==== X (C.P)
X = 36*100/16 = Rs. 225
Hence C.P of article = rs.225
Hope this helps
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