Renu took part in a 100m race she tripped and fell after running 80 m 50 cm how much distance did she have left to run
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Answered by
51
Maximum distance to be covered in race = 100 m
distance covered = 80 + 50/100 = 80 + 0.5 = 80.5m
distance she left to run = 100 -80.5 = 19.5 m
distance covered = 80 + 50/100 = 80 + 0.5 = 80.5m
distance she left to run = 100 -80.5 = 19.5 m
Answered by
46
It is given that Renu took part in a 100 m race, in which she tripped and fell after running 80 m 50 cm.
Hence,
Total length of the playfield of race is 100 m.
She tripped and fell after covering 80 m 50 cm in a 100 m race.
On observing the situation, we get that if we remove the length of covered area from the total area, we will get the distance which she have left to run.
Now,
Distance left to run = total distance - distance covered.
= > Distance left to run = 100 m - 80 m 50 cm.
Now,
Converting 80 m 50 cm into metre,
We know, 1 m = 100 cm & 1 / 100 m = 1 cm
Therefore,
80 m 50 cm = 80.5 m
Hence,
Distance left to run = 100m - 80.5 m
Distance left to run = 19.5 m
Therefore,
The distance which she left to run is 19.5 m in length.
Hence,
Total length of the playfield of race is 100 m.
She tripped and fell after covering 80 m 50 cm in a 100 m race.
On observing the situation, we get that if we remove the length of covered area from the total area, we will get the distance which she have left to run.
Now,
Distance left to run = total distance - distance covered.
= > Distance left to run = 100 m - 80 m 50 cm.
Now,
Converting 80 m 50 cm into metre,
We know, 1 m = 100 cm & 1 / 100 m = 1 cm
Therefore,
80 m 50 cm = 80.5 m
Hence,
Distance left to run = 100m - 80.5 m
Distance left to run = 19.5 m
Therefore,
The distance which she left to run is 19.5 m in length.
Anonymous:
ye bittu bahiya
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