Replace * in 27*20 with a smallest number suchthat it becomes divisible by 3, 7,9and 11.
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Answer:
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Step-by-step explanation:
first 2-6-2-4-2-4&-5
Answer:
i) 64 M 3
The given number = 64 M 3
For a number to be divisible by 3 sum of digits must be divisible by 3.
Sum of its digits = 6 + 4 + 3 = 13
The number next to 13 which is divisible by 3 is 15
Required smallest number = 15 - 13 = 2
Therefore, value of M is 2.
(ii) 46 M 46
The given number = 46 M 46
For a number to be divisible by 3 sum of digits must be divisible by 3.
Sum of its digits = 4 + 6 + 4 + 6 = 20
The number next to 20 which is divisible by 3 is 21
Required smallest number = 21 - 20 = 1
Therefore, value of M is 1.
(iii) 27 M 53
The given number = 27 M 53
For a number to be divisible by 3 sum of digits must be divisible by 3.
Sum of its digits = 2 + 7 + 5 + 3 = 17
The number next to 17 which is divisible by 3 is 18
Required smallest number = 18-17=1
Therefore, value of M is 1.