Replace the * with the smallest digit to make it divisible by 11
45*53
PLEASE ANSWER !!!!
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Answer:
Step-by-step explanation:
let us assume the no. to be as 45a53,
for it to be divisible by 11,
(4+a+3)-(5+5) = 11n (as divisibility rule for 11 is : difference between even places and odd places should be a multiple of 11)
7+a-10 =11n
a= 11n+3
for n=0 ,a=3
for n=1 ,a=14
for n=2,a=25
and for any value other than n=0 value of a does not lie in between 0 to 9 (since a is a digit it should in between 0 to 9)
So, so only possible value of a is 3
so the required no. is 45353
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